below is part of mail/puzzle he sent to me
this is a real brain teaser..
WARNING:the answer may seem logically correct as the figures here have been arbitarilly chosen..
ok..so there's this girl who reaches the station at 6am everyday.Her driver comes and picks her up and they reach home by 7am.
Now,one day the girl reaches the station early..at 5am and decides to walk towards her house.She meets the driver on the way and that day they reach home by 6.40 am..
The ques is..for how long was the girl walking??..and NO the answer is NOT 20 mins....
Best of luck folks!
[red][b]please inform me the ans and the way u found it[/red][/b]
and here is original incorrect solution i sent to my cousin
here is final (hopefully correct) solution
and here is the logic
- let distance from station to home be x km
- since driver picks up girl at six (obviously he would travel from home such that he picks her immediately) and reaches at seven, x km traveled in 1 hr. driver speed= x km/hr
- since it takes him 1 hr from station to home, it takes him 1 hr from home to station. so he starts from home at 5 am
- girl too started at 5 am that day. let distance [from station] at which they meet be z km
- let girl speed be y km/hr
- girl travels z km at y km/hr, so time = z/y hr
- driver travels x-z km at x km/hr, so time= (x-z)/x
- equate time by girl to time by driver to get first equation
- since girl started at 5 and reached at 6:40, total time [girl on foot+ girl in car] = 1 hour 40 minutes. 2nd equation obtained
- since driver started at 5 and reached home at 6:40, his journey to meeting point took half of 1 hour 40 minutes i.e. 50 minutes. his distance till meeting place = x-z and time= 50 minutes and his speed as already established is x km/hr. 3rd equation obtained. 3 variables 3 equations the problem is solved!